Answer:
Let x= 1 peso coin
y= 5 peso coin
[tex]x= y+16. eqn1\\ x +y=88. eqn2[/tex]
Substitute eqn. 1 to eqn. 2
[tex]x+y=88\\ y+16+y=88\\ 2y+16=88\\ 2y=88-16\\ 2y=72\\ \frac{2y}{2} =\frac{72}{2} \\ y=36[/tex]
Using eqn.1 substitute the y value to find the value of x
[tex]x=y +16\\ x=36+16\\ x=52[/tex]
Hence, there are 52 pieces of one peso coin and 36 five peso coin
~hope it helps ^-^
