a gas occupies 250 ml at 684 torr and 30 degrees celsius when the pressure is charged to 460 torr what temperature in degrees celsius is needed to maintain the same of volume?​

Sagot :

Given:

[tex]P_{1} = \text{684 torr}[/tex]

[tex]T_{1} = \text{30°C + 273 = 303 K}[/tex]

[tex]P_{2} = \text{460 torr}[/tex]

Unknown:

[tex]T_{2}[/tex]

Solution:

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]

[tex]T_{2} = T_{1} × \frac{P_{2}}{P_{1}}[/tex]

[tex]T_{2} = \text{303 K} × \frac{\text{460 torr}}{\text{684 torr}}[/tex]

[tex]T_{2} = \text{204 K}[/tex]

[tex]T_{2} = \text{204 K} - 273[/tex]

[tex]\boxed{T_{2} = -\text{69°C}}[/tex]

[tex]\\[/tex]

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