Answer:
Solving the equation simultaneously,
[tex]\left \{ {{y=-2-4x} \atop {y=x^2-4x-3}} \right. \\ SubstitutionPrinciple\\ -2-4x=x^2-4x-3\\ -2-4x+2=x^2-4x-3+2\\ -4x=x^2-4x-1\\ -4x+4x=x^2-4x+4x-1\\ 0=x^2-1\\ FactoringTheExpression\\ x^2-1\\ (x+1)(x-1)\\ Roots:x=1,x=-1\\ \\ When,x=1\\y=-2-4(1)\\y=-2-4\\ y=-6\\ \\ When,x=-1\\ y=-2-4(-1)\\ y=-2+4\\ y=2\\ \\ SolutionPairs:(-1,2),(1,-6)[/tex]
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-Pantonal
