find the dimension of a rectangle where the altitude is four seventh of the base and the perimeter is 330 feet.

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find the dimension of a rectangle where the altitude is four seventh of the base and the perimeter is 330 feet.

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Given:
let x = base
[tex]height=\frac{4}{7} x[/tex]
P = 330

Solution:
[tex]P = 330 = 2(\frac{4}{7} x ) + 2x[/tex]
multiplying both sides by 7 you get,
2310 = 8x + 14x
22x = 2310
x = 105

[tex]height=\frac{4}{7} (105)[/tex]
height = 60

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