for this you have to start from the inside (i can't think of a better word haha) and work your way to the one that isn't in brackets
Edit: (didn't realize you already have a given x value and you're not solving for x)
4x-3[x-2(x+3)]
=4x-3[x-2x-6]
=4x-3[-x-6]
=4x+3x+18
=7(1) +18
=25
