Answered

1. Find the square of 41 using the concept of special product.
2. Find the product of 57 and 43 using the special product.
3. Find the square of 39 using special product.

Sagot :

Rodriguezmina94viz
(40+1)(40+1)

Solution:
=(40)(40)+2(40)+(1)(1)
=1600+80+1
=1681

(50+7)(40+3)

Solution:
FOIL METHOD
=(50)(40)+(150+280)+(7)(3)
=2000+430+21
=2451

(30+9)(30+9)

Solution:
=(30)(30)+2(270)+(9)(9)
=900+540+81
=1521
VilesXviz
1.) 
special product: Formula
(x-y)²=x²-2xy+y²

(50-9)²=50²-2(50)(9)+9²
(50-9)²=1681

2.)
special product: Formula
(x+y)(x-y)=x²-y²

(50+7)(50-7)=50²-7²
(50+7)(50-7)=2451

3.)
special product: Formula
(x+y)²=x²+2xy+y²

(30+9)²=30²+2(30)(9)+9²
(30+9)²=1521