Answer:
THE SUM OF THE FIRST 25 TERMS OF THE ARITHMETIC SEQUENCE 4,9,14,19,24.....
ARITHMETIC SEQUENCE in mathematical term is a set of numbers that are in order.
example: 3, 5, 7, 9,..
this sequence has a difference of 2 between each number
where:
Term it is the number in the sequence.
Denote this partial sum by Sn, Then
Sn= a1 + (n-1) d,
where n is the number of terms, a1 is the first term and d is the difference of each number.
First find the 25th term of arithmetic sequence 4, 9, 14, 19, 24.
( ∑(k=0)^(n-1)( a+kd)= n/2 ( 2a+(n-1)d
where the given is
a= 4 ( the first term)
d= 5 ( the " Common difference" between each number or term
n= 25 ( how many terms to add up )
Solution: ∑( 4 + k * 5) = 25/ 2 ( 2(4) + (25-1) 5
= 25/2 ( 128)
= 12.5 ( 128)
= 1600
therefore the answer is 1600.
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