Solution:
Step 1: Calculate the molar mass of CaCO₃.
molar mass = (40.08 g/mol × 1) + (12.01 g/mol × 1) + (16.00 g/mol × 3)
molar mass = 100.09 g/mol
Step 2: Calculate the percentage composition of CaCO₃.
General Formula:
[tex]\text{percent composition} = \frac{\text{atomic mass of an element × number of atoms in a compound}}{\text{molar mass of compound}} × 100[/tex]
For %Ca
[tex]\text{\%Ca} = \frac{\text{40.08 g/mol × 1}}{\text{100.09 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%Ca = 40.04\%}}[/tex]
For %C
[tex]\text{\%C} = \frac{\text{12.01 g/mol × 1}}{\text{100.09 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%C = 12.00\%}}[/tex]
For %O
[tex]\text{\%O} = \frac{\text{16.00 g/mol × 3}}{\text{100.09 g/mol}} × 100[/tex]
[tex]\boxed{\text{\%O = 47.96\%}}[/tex]
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