what is the height of the parallelogram with an area of 66 inches² and a base of 11 inches​

Sagot :

Answer:

Given:

A = 66 inches²

base = 11 inches

height= ?

Solution

A = bh

[tex]66 \: inches {}^{2} = 11 \: inches(h)[/tex]

[tex] \frac{66 \: inches {}^{2} }{11 \: inches} = \frac{11 \: inches(h)}{11 \: inches} [/tex]

cancel 11 inches in both numerator and denominator in the right Equation .

[tex]6 \: inches \: = h[/tex]

[tex]height = 6 \: inches[/tex]

Checking:

A = bh

66 inches² = 11 inches (6 inches)

66 inches² = 66 inches²