[tex] \large \green{ \dashrightarrow{ \bold{PROBLEM:}}}[/tex]
solve log x to base 3 + log x squared to base 9 =2?
[tex] \large \green{ \dashrightarrow{ \bold{SOLUTION:}}}[/tex]
[tex] \bold{ log_{3}(x) + log_{9}(x {}^{2} ) } \\ \bold{2 \: log_{9}(x) + log_{9}(x {}^{2} ) = 2} \\ \bold{ log_{9}(x {}^{2} ) + log_{9}(x {}^{2} ) = 2} \\ \bold{2 \: log_{9}(x {}^{2} ) = 2} \\ \bold{ log_{9}(x {}^{2} ) = 1} \\ \bold{x {}^{2} = 9 {}^{1} = 9} \\ \bold{x = 3} \\ \\ \bold{Check} \\ \bold{ log_{3}(3) + log_{9}(9) = 2} \\ \bold{1 + 1 = 2} \\ \\ \bold{log(base \: a)x = \frac{[log(base \: b)x]}{[log(base \: b)a]} } \\ \bold{ log_{3}(x) = \frac{[ log_{9}(x) ]}{ [log_{9}(3) ]} } \\ \ \bold»\color{darkviolet} \: \bold{ log_{3}(x) = 2 log_{9}(x) }[/tex]
[tex] \large \color{cyan}\dashrightarrow \color{indigo} { \bold{Carry\: On\: Latex}}[/tex]
