Juanyyaneviz
Answered

what Is the distance of t=1min​

Sagot :

Demongirl01viz

Answer:

Total distance travelled in going and coming back

D = 30m + 30m = 60 m

Total time taken in going and coming back

t= 1 min + 1.5 min =2.5 min

= 2.5 60 s

= 150 s

Average speed = \frac{totaldis\tan ce\ \ travelled}{total\ time\ of\ travel}=\ \frac{60m}{150s}

total time of travel

totaldistance travelled

=

150s

60m

=0.4 m\ s^{-1}m s −1

Explanation:

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