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GAY LUSSAC'S LAW (SHOW YOUR SOLUTION)
A steel tank containing a sample of gas has a pressure of 760 torr at 30°C. Find the new pressure if the temperature is raised to 60°C.

Sagot :

Given:

[tex]P_{1} = \text{760 torr}[/tex]

[tex]T_{1} = \text{30°C + 273 = 303 K}[/tex]

[tex]T_{2} = \text{60°C + 273 = 333 K}[/tex]

Unknown:

[tex]P_{2}[/tex]

Solution:

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]

[tex]P_{2} = P_{1} × \frac{T_{2}}{T_{1}}[/tex]

[tex]P_{2} = \text{760 torr} × \frac{\text{333 K}}{\text{303 K}}[/tex]

[tex]\boxed{P_{2} = \text{835 torr}}[/tex]

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