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a rectangular pyramid has a base measuring 10dm by 6dm.if each face is 8dm high,find its total surface areaa rectangular pyramid has a base measuring 10dm by 6dm.if each face is 8dm high,find its total surface area​

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C41992viz

Answer:

202.044 dm²

Step-by-step explanation:

TSA = SUM OF ALL THE ARE OF LATERAL AND BASE

  • THERE ARE TWO EQUAL LATERAL AREA FORM AS TRIANGLES (HAVING BASE 10 AND 6)

TSA=

= 2(area of the triangle with the base of 10) + 2(area of the triangle with the base 6) + area of the rectangular base

  • Note area of a triangle
  • [tex] = \frac{1}{2}( base)(height)[/tex]
  • height of each triangle was computed using Pythagorean theorem (i draw it)

[tex] = 2( \frac{1}{2} (10)( \sqrt{73} )) + 2( \frac{1}{2} (6)( \sqrt{89} )) + 6(10) \\ = 202.044[/tex]

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