Raymondsayabocisidroviz
Answered


[tex] \sqrt{x + 9} = 1 + \sqrt{x} [/tex]
Need solutions po.
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Sagot :

Chlydreaviz

Step-by-step explanation:

[tex] \sqrt{x + 9} = 1 + \sqrt{x} \\ ( \sqrt{x + 9} ) {}^{2} = 1 + ( \sqrt{x} ) {}^{2} \\x + 9 = 1 + x \\ x = 1 + x - 9 \\ x = x - 8[/tex]

correct me if I'm wrong