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A bag contains 4 white balls, 6 yellow balls, and 5 red balls. In how many ways can 6 balls be chosen if there must be 2 balls of each color?

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Answer:

3 times

Step-by-step explanation:

(4)white balls ÷ (2) because there must be 2 balls in each colors.

4÷2=2

(5) red balls ÷ (2) because there must be 2 balls in each colors.

5÷2= 2.5. but disregard the (.5) because it doesn't meet the requirements of 2 balls in each color. .5 only represent 1 ball. so the answer here is 2

(6) yellow balls ÷ (2) because there must be 2 balls in each colors.

6÷2 = 3

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