Answer:
The x- and y-intercepts of the linear equation 4x – 3y = 12 is ___
a. (3,0), (0,-4)
b. (-3,0), (0,-4)
c. (3,0), (0,4)
d. (-3,0), (0,-4)
Objective
Solution
[tex]\tt{x_{(intercept)} : 4x - 3y = 12}[/tex]
[tex]\tt{x_{(intercept)} : 4x - 3(0) = 12}[/tex]
[tex]\tt{x_{(intercept)} : \frac{4x}{4} = \frac{12}{4}}[/tex]
[tex]\boxed{\tt{x_{(intercept)} : x = 3 \: or \: (3,0)}}[/tex]
[tex]\tt{y_{(intercept)} : 4x - 3y = 12}[/tex]
[tex]\tt{y_{(intercept)} : 4(0) - 3y= 12}[/tex]
[tex]\tt{y_{(intercept)} : \frac{-3y}{-3} = \frac{12}{-3}}[/tex]
[tex]\boxed{\tt{y_{(intercept)} : y = -4 \: or \: (0,-4)}}[/tex]
The answer is: A. (3,0), (0,-4)