Answer:
[tex]f(x) = {2x}^{2} - 7x + 3 \\ =( 2x - 1)(x - 3) \\ (2x - 1) = 0 \\ 2x - 1 +1 = 0 + 1 \\ 2x = 1 \\ x = \frac{1}{2} \\ ( \times - 3) = 0 \\ x - 3 + 3 = 0 + 3 \\ x = 3[/tex]
[tex]x = \frac{1}{2 } \\ f( \frac{1}{2} ) = 2( \frac{1}{2}) {}^{2} - 7( \frac{1}{2} ) + 3 \\ = 2( \frac{1}{4}) - \frac{7}{2} + 3 \\ = \frac{2}{4} - \frac{7}{2} + 3 \\ = \frac{1}{2 } - \frac{7}{2} + 3 \\ = 0[/tex]
[tex]x = 3 \\ f(3) = 2(3) {}^{2} - 7(3) + 3 \\ = 2(9) - 21 + 3 \\ = 18 - 21 + 3 \\ = 0[/tex]
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correct me if I'm wrong
