Direction:Solve the given problem.
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1. m∠A = m∠C, m∠C = 65°
m∠B + 65° = 180°
m∠B = 115°
m∠B = m∠D, m∠D = 115°
2. m∠S = m∠R, m∠R = 50°
m∠P + 50° = 180°
m∠P = 130°
m∠P = m∠Q, m∠Q = 130°
3. AB = AD, AD = x + 2
BC = DC, DC = 2x + 1
Perimeter is the sum of the length of all sides.
48 = AB + AD + BC + DC
48 = (x + 2) + (x + 2) + (2x + 1) + (2x + 1)
48 = 6x + 6
6x = 42
x = 7
AB = AD = x + 2 = (7) + 2 = 9
BC = DC = 2x + 1 = 2(7) + 1 = 15