find the 40th term of the sequences; 5,7,9,11​

Sagot :

Answer:

[tex]a_{40}=83[/tex]

Step-by-step explanation:

Use arithmetic sequence:

[tex]a_{n}=a_1+(n-1)d[/tex]

[tex]a_n[/tex] = the nᵗʰ term in the sequence

[tex]a_1[/tex] = the first term in the sequence

[tex]d[/tex] = the common difference between terms

[tex]a_{40}=a_1+(40-1)d[/tex]

[tex]d = (a_2-a_1)[/tex]

[tex]d = (7-5)[/tex]

[tex]d=2[/tex]

[tex]a_{40}=5+(40-1)2[/tex]

[tex]a_{40}=5+(39)2[/tex]

[tex]a_{40}=83[/tex]