1. If tree coins are tossed, what is the probability distribution of the values
of the random variable having two heads?
1/8
1/4
b. 3/8
d. 5/8​


Sagot :

Answer:

b. 3/8

Step-by-step explanation:

Let E2 = event of getting 2 heads. Then,

E2 = {HHT, HTH, THH}

and, therefore, n(E2) = 3.

Therefore, P(getting 2 heads) = P(E2) = n(E2)/n(S) = 3/8.

Answer:

1/4

Step-by-step explanation:

There are 4 possibilities: 0heads, 1head, 2heads, and 3 heads. We need 2heads which is 1 out of the 4 possibilities.