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If Logx (1 / 8) = - 3 / 2, then x is equal to



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Mlcparra16viz
Example:
[tex]log_2(8)=?[/tex]
[tex]2^?=8 \\ 2^?=2^3[/tex]
Therefore the logarithm is 3 so:

[tex]x^{-3/2}=1/8 \\ \frac{1}{\sqrt{x^3} }= \frac{1}{8} \\ \sqrt{x^3} =8 \\ x^3=64 \\ x= \sqrt[3]{64} =4[/tex]

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