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1. How many terms are there in an arithmetic sequence with a common difference of 4 and with first and last terms 3 and 59, respectively?

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Jeremiaviz
ormula:
             
Asked:
               Number of terms or n
Solution:
 
        59 = 3 + (n - 1) 4
        59 = 3 + 4n - 4
        59 = 4n - 1
        59 + 1 = 4n
        60 = 4n
        60 / 4 = 4n /4
        15 = n
Answer:
                   There are 15 terms in the given arithmetic sequence
Mlcparra16viz
Formula:
[tex]n= \frac{a_n-a_1}{d} +1= \frac{59-3}{4} +1=15[/tex]

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