Sagot :
[tex]x \to the \ cost \ of \ pants \\\\ y \to the \ cost \ of \ blouse \\\\\\ x+y=1200 \\\\ x=y+600 \\\\\\ y+600+y=1200 \\\\ 2y=1200-600 \\\\ 2y=600 \ \ \ |:2 \\\\ \boxed{y=300 } \\\\ x=300+600 \\\\ \boxed{x=900}[/tex]
We let the price of a blouse be x, this would make the price of a pair of pants be x+600. So we have:
1200 = x + (x+600)
1200 - 600 = 2x
600 = 2x
300 = x
Therefore the cost of the blouse is P300 and a pair of pants is: 300+600 = P900.
1200 = x + (x+600)
1200 - 600 = 2x
600 = 2x
300 = x
Therefore the cost of the blouse is P300 and a pair of pants is: 300+600 = P900.