the square root of 4 more than a number is equal to 2less than the number find the number

Sagot :

Answer:

Let x represent a number.

[tex] \sqrt{x + 4} = x - 2[/tex]

Multiply bothsides by the index.

[tex] {}^{2} ( \sqrt{x + 4} = x - 2) {}^{2} [/tex]

[tex]x + 4 = (x - 2) {}^{2} [/tex]

[tex]x + 4 = {x}^{2} - 2x - 2x + 4[/tex]

[tex]x + 4 = {x}^{2} - 4x + 4[/tex]

[tex] {x}^{2} - 4x - x + 4 - 4 = 0[/tex]

[tex] {x}^{2} - 5x = 0[/tex]

[tex]x(x - 5)[/tex]

[tex]x = 0[/tex]

[tex] x = 5[/tex]