Answered

In circle, what is the standard form of x^2 + y^2 + x – 2y = -1​

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SOLUTION

  • x²+y²+x-2y = -1
  • x²+x+y²-2y = -1
  • x²+x + 1/4 + y²-2y +1 = -1 + 1 + 1/4
  • (x+ 1/2)² + (y - 1)² = 1/4

ANSWER

  • (x+ 1/2)² + (y - 1)² = 1/4

Wherein the Center is at (-1/2,1) and the radius is 1/2

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