Find the product of the following

1. (4xy-3)3 =

____________________

2. (3x+2)3 =

____________________

3. (2p+3q2)3 =

____________________

4. (2x-1)3

=

____________________

5. (x-5)3

=

_________________​


Sagot :

1.(4xy-3)3 =

-12xy-9

2.(3x+2)3 =

-9x+6

3.(2p+3q2)3 =

-6p+18q

4.(2x-1)3 =

-6x-3

5.(x-5)3 =

-3x-15

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multiply 3 to both term, that is inside the parenthesis.

(4xy-3)3=

(3*4xy)-(3*3)= 12xy-9

(3x+2)3=

(3*3x)+(3*2)= 9x+6

(2p+3[tex]q^{2}[/tex])3=

(3*2p)+(3*3[tex]q^{2}[/tex])= 6p+9[tex]q^{2}[/tex]

(2x-1)3

(3*2x)-(3*1)= 6x-3

(x-5)3

(3*x)-(3*5)= 3x-15