Sagot :
1.(4xy-3)3 =
-12xy-9
2.(3x+2)3 =
-9x+6
3.(2p+3q2)3 =
-6p+18q
4.(2x-1)3 =
-6x-3
5.(x-5)3 =
-3x-15
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multiply 3 to both term, that is inside the parenthesis.
(4xy-3)3=
(3*4xy)-(3*3)= 12xy-9
(3x+2)3=
(3*3x)+(3*2)= 9x+6
(2p+3[tex]q^{2}[/tex])3=
(3*2p)+(3*3[tex]q^{2}[/tex])= 6p+9[tex]q^{2}[/tex]
(2x-1)3
(3*2x)-(3*1)= 6x-3
(x-5)3
(3*x)-(3*5)= 3x-15