A solution is prepared by condensing 4.00 L of a gas measured at 27°C and 748 mmHg pressure, into 58.0 g of benzene. Calculate the freezing point of this solution.

Sagot :

Answer:

First, we are using the ideal gas law to get n the number of moles:

PV = nRT

when P is the pressure = 748 mmHg/760 = 0.984 atm

V is the volume = 4 L

R is ideal gas constant = 0.0821

T is the temperature in Kelvin = 300 K

∴ n =  0.984atm*4L/0.0821*300

      = 0.1598 moles

when the concentration = moles * (1000g / mass)

                                        = 0.1598 * (1000g / 58 g )

                                        = 2.755 M

when the freezing point = 5.5 °C

and Kf = - 5.12 °C/m

∴ the freezing point for the solution = 5.5 °C + (Kf*m)

                                                           = 5.5 °C - (5.12°C/m * 2.755m)

                                                           = -8.6 °C

Explanation: