Answered

Solve the following systems by substitution:
y = 2x + 3
4x – 3y = 1

Sagot :

Mlcparra16viz
We just substitute the value of y using the first equation on the second equation:
Since y = 2x + 3

4x - 3y = 1
4x - 3(2x + 3) = 1
4x - 6x - 9 = 1
-2x = 10
x = -5

So:
y = 2x + 3
y = 2(-5) + 3 = -10 + 3 = -7