Pa help po please...

[tex]10.) \: \sqrt{ \frac{25}{36} } = \sqrt{ \frac{ {5}^{2} }{ {6}^{2} } } = \frac{5}{6} [/tex]
[tex]11.) \: \sqrt{ \frac{63}{25} } = \sqrt{ \frac{ {3}^{2} \times 7}{ {5}^{2} } } = \frac{3 \sqrt{7} }{5} [/tex]
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