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Solve the following systems by elimination:
3x + 2y = 40
x – 7y = - 2

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Mlcparra16viz
3x + 2y = 40 ... [1]
x - 7y = -2 ... [2]

[1] - 3[2]
3x + 2y = 40
-3x + 21y = 6
     23y = 46
       y = 2

So:
x - 7y = -2
x - 7(2) = -2
x - 14 = -2
x = 12

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