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Solve the following systems by substitution method:
x + 3y = 4
y + x = 0

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Mlcparra16viz
The second equation can be:
y + x = 0 
x = -y

So:
x + 3y = 4
-y + 3y = 4
2y = 4
y = 2

x = -y
x = -2