Answered

Solve the following systems of equations by elimination:
x + 3y = -4
x + y = 0

Sagot :

Mlcparra16viz
x + 3y = -4 ... [1]
x + y = 0 ... [2]

[1] - [2]
x + 3y = -4 
-x -y = 0    
  2y = -4
    y = -2

So:
x + y = 0 
x - 2 = 0
x = 2