1.Find the area of the square whose sides are each (3b – 1) meters long. *

A. 6b² - 9b + 1 square meters
B. 9b² - 6b + 1 square meters
C. b² - 6b + 9 square meters
D. 9b² - b + 6 square meters

2.How many terms does ( 6n – p )² have in the result? * *

A. 1
B. 2
C. 3
D. 4 ​


Sagot :

Answer:

1.Find the area of the square whose sides are each (3b – 1) meters long.

Solution:

A = a²

A = (3b – 1)²

A = 9b² - 6b + 1

Final Answer: B. 9b² - 6b + 1 square meters.

2.How many terms does (6n – p)² have in the result?

Solution:

(6n – p)²

= 36n² - 6np² + p²

36n² = 1 term

-6np² = 1 term

p² = 1 term

= three terms

Final Answer: C. 3

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