1.Find the area of the square whose sides are each (3b – 1) meters long.
Solution:
A = a²
A = (3b – 1)²
A = 9b² - 6b + 1
Final Answer: B. 9b² - 6b + 1 square meters.
2.How many terms does (6n – p)² have in the result?
Solution:
(6n – p)²
= 36n² - 6np² + p²
36n² = 1 term
-6np² = 1 term
p² = 1 term
= three terms
Final Answer: C. 3
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