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what is the equation of the hyperbola which has vertices (+-5,0) and one focus at (6,0)​

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Joshmagubatviz
The standard form equation of the hyperbola:
x² / a² - y² / b² = 1
a = 5,
a² = 25
c = 6
c² = a² + b²
36 = 25 + b²
b² = 36 - 25
b² = 11
Answer:
x²/25 - y²/11 = 1

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