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A wire with a length of (x 2 + 10x + 21) cm will be used in making a series circuit. If an electrician decided to make an (x + 3) bulb series circuit in which the bulbs are of equal distances, how long is the distance in cm of one bulb to the other?

(I really need it, with a 2-3 sentence explanation.)

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In the given problem, apply your knowledge in algebra and basic mathematics specially in solving word problem about solving polynomials.

Given

A wire with a length of (x 2 + 10x + 21) cm

(x + 3) bulb series circuit

Solution

Divide the two polynomials using synthetic division.

x + 3 = 0

x = -3 | x² + 10x + 21

| 1 | 10 | 21

| | -3 | -21

1 | 7 | 0 → x + 7

x² + 10x + 21 ÷ x + 3 = x + 7

Explanation

The (x² + 10x + 21) is a quadratic equation having a factor of x + 3. You can divide the binomial x + 3 from the quadratic equation to get the other factor.

Answer

(x+7) cm

Learn more about synthetic division here at

https://brainly.ph/question/2250915

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