2. The area A of rectangle varies jointly as the length 1
and the width w and A= 180 cm² when l = 9cm and
w = 5cm. Find the area of a rectangle whose length is
20cmand whose width is 5cm.​


Sagot :

JOINT VARIATION

EQUATION:

[tex]A = klw[/tex]

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First, solve for the constant of variation k using the formula [tex] k = \frac{A}{lw}[/tex] .

[tex]180 = k(9)(5)[/tex]

[tex]k = \frac{180}{(9)(5)}[/tex]

[tex]k = \frac{180}{45}[/tex]

[tex]k = 4[/tex]

Therefore, the constant of variation is 4.

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Then, find the area of a rectangle whose length is 20cm and whose width is 5cm. using the equation [tex]A = 4lw[/tex] where 4 is the constant of variation k.

[tex]A = klw[/tex]

[tex]A = (4)(20)(5)[/tex]

[tex]A = (4)(100)[/tex]

[tex]A = 400[/tex]

Final Answer:

[tex]A = 400[/tex]

The area of a rectangle is 400cm².

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