Answered

How many liters of water should be added to 20 liters of a 30% sulfuric acid solution to reduce it to a 15% solution?

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KimJongInEXO011494viz
water + water = water
0.7*20 + 1*x = 0.85(20+x)
70*20 + 100x = 85*20 + 85x
15x = 15*20x = 20 liters (amount of water to add)