A girl walked for 30 minutes. She noticed that she traveled farther in the first 15 minutes of her walk than in the second 15 minutes. What can she conclude about her walk?
A She walked over many hills.
B Her average speed was faster during the first half of her walk.
C She walked in two different directions.
D She was walking at a constant speed.

According to straight line motion, the speed is directly proportional to the distance (s = d/t). Therefore, if there is an increase in speed, the distance increases also when time is constant.

Since the problem states that the girl noticed that she walked farther on her first 15 minutes. This means that she walked faster than the second 15 minutes of her walk.

To observe more, let us use computations to examine the connection between speed and distance.

Example:

1st scenario:

Speed = 2 m/s

Time = 15 minutes x 60s/ 1 minute = 900 s

d = ?

Solution:

Speed = d/t

2 m/s = d /900 s

d = speed x time

d = (2m/s)(900 s)

d = 1,800 m

2nd scenario:

Speed = 3 m/s

Time = 15 minutes = 900 s

d = ?

Solution:

Speed = d/t

d = speed x time

d = (3 m/s)(900 s)

d = 2,700 m

Therefore, through computation, we can say that an increase in speed means increase in distance.

To learn more about this topic, just click on the following links:

Difference between distance and displacement

https://brainly.ph/question/106226

How to solve for distance

https://brainly.ph/question/2618924

Connection of distance to mass

https://brainly.ph/question/2524814

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