if f varies jointy as q2 and h, and f=36 when q=2 and h = 3, find f when q= 4 and h = 5. ( a: 48. b: 240. c: 60. d: 15. ) please put your solution.​

Sagot :

Answer:

The value of f is 240.

Step-by-step explanation:

Mathematical  Equation:

[tex]\LARGE\text{$f=kq^2h$}[/tex]

For the constant of variation (k):

Given:   [tex]f=36[/tex],   [tex]q=2[/tex],   [tex]h=3[/tex]

Find:   [tex]k=?[/tex]

Formula:   [tex]f=kq^2h[/tex]

Solution:

[tex]f=kq^2h\\36=(2)^2(3)k\\36=(4)(3)k\\36=12k\\\frac{36}{12}=\frac{12k}{12}\\\boldsymbol{3=k}[/tex]

For the value of f:

Given:   [tex]k=3[/tex],   [tex]q=4[/tex],   [tex]h=5[/tex]

Find:   [tex]f=?[/tex]

Formula:   [tex]f=kq^2h[/tex]

Solution:

[tex]f=kq^2h\\f=(3)(4)^2(5)\\f=(3)(16)(5)\\\boxed{\boldsymbol{f=240}}[/tex]

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