Sagot :
Answer:,Ayan po Step-by-step explanation:Figure 1 below shows a circle whose center is at point (4, 3) with a radius of 2.How do we find the standard form equation of this circle?We put the center coordinates (4, 3) into the a and b variables and we square the radius for r²(x -4)² + (y -3)² = 4By multiplying this out, we get the general formx² -8x + 16 +y² -6y + 9 = 4x² +y² -8x -6y +21 = 0. Sorry kung kulang kulang,I'm sorry po talaga
PRECALCULUS
Remember
Equation of a circle
- (x-h)²+(y-k)² = r²
where
- center = (h,k)
- radius = r
Question:
- (x+1)² + (y+3)² = 16
Solution:
- (x-(-1))² + (y-(-3)² = 4²
where h = -1
k = -3
r = 4
ANSWER
- Center (-1,-3)
- Radius is 4