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How many carbon atoms are there in 0.75 mole of C6H12O6. Pa show solution po

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Solution:

[tex]\text{number of C atoms = 0.75 mol C₆H₁₂O₆} × \frac{\text{6 mol C}}{\text{1 mol C₆H₁₂O₆}} × \frac{\text{6.022 × 10²³ C atoms}}{\text{1 mol C}}[/tex]

[tex]\boxed{\text{number of C atoms = 2.71 × 10²⁴ atoms}}[/tex]

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