Answered

If r varies directly as p and inversely as u, and r=2 when p=18 and u= 2. Find u when r=1 and p=36.

Sagot :

Nicorobin2588viz

Step-by-step explanation:

let k be the constant of variation

[tex]r (2)= \frac{kp(18)}{u(2)} [/tex]

multiply both sides by 2 to cancel the denominator

4=k18

divide both sides with 18 to get the constant of variation

4/18=k

or 2/9=k

[tex]r = \frac{ \frac{2}{9}p }{u} [/tex]

[tex]r(1) = \frac{k( \frac{2}{9})p(36) }{u} [/tex]

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