Answer:
[tex]13 \frac{8}{9} \: liters[/tex]
Step-by-step explanation:
Let:
d-distance
l-liters of gasoline
k-constant
[tex]d = kl[/tex]
If
[tex]d = 90 \: km \: and \: l = 5 \: l[/tex]
then
[tex]k = \frac{d}{l} = \frac{90}{5} = 18 \: (constant)[/tex]
For
[tex]d = 250 \: km[/tex]
then
[tex]l = \frac{d}{k} = \frac{250}{18} = 13 \frac{8}{9} \: liters[/tex]
Therefore, 13 8/9 liters is needed for a 250-km trip.