Suppose z varies directly as x and inversely as y. If z=8 when x=16 and y=10, What is x when z=9 and y=15. *​

Sagot :

Answer:

[tex]x = 27[/tex]

Step-by-step explanation:

[tex]z = \frac{kx}{y} [/tex]

[tex]8 = \frac{k16}{10} [/tex]

[tex]8(10) = k16[/tex]

[tex]80 = k16[/tex]

[tex] \frac{80}{16} = \frac{k16}{16} [/tex]

[tex]k = 5[/tex]

[tex]9 = \frac{5x}{15} [/tex]

[tex]9(15) = 5x[/tex]

[tex]135 = 5x[/tex]

[tex] \frac{135}{5} = \frac{5x}{5} [/tex]

[tex]x = 27[/tex]