Answer:
d)6x⁴y³z³
e) 5y²/x²
f) y⁶/2x⁵
Step-by-step explanation:
NOTE: Im assuming that in d), the 3 & second 2 in the first factor and the 2 in the second factor are exponents.
Learning Competencies:
- Dividing Polynomials with Exponents
- Multiplying Polynomials with Exponents
d) (2x³y²z)(3xyz²) = 2•3 [x^(3+1)] [y^(2+1)] [z^(1+2)]
= 6x⁴y³z³
e) 40x⁴y⁶÷8x⁶y⁴= 40/8 [x^(4-6)] [y^(6-4)]
5(x^-2)y²
=5y²/x²
f) 6x⁴y⁶÷12x⁴x⁵= 6/12 {[x^[4-(4+5)]} (y⁶)
1/2 (x^-5)(y⁶)
=y⁶/2x⁵
