Solution:
Step 1: Calculate the molar mass of Ba(NO₂)₂.
molar mass = (137.3 g × 1) + (14.01 g × 2) + (16.00 g × 4)
molar mass = 229.32 g
Step 2: Calculate the mass of Ba(NO₂)₂.
[tex]\text{mass of Ba(NO₂)₂ = 4.50 mol Ba(NO₂)₂} × \frac{\text{229.32 g Ba(NO₂)₂}}{\text{1 mol Ba(NO₂)₂}}[/tex]
[tex]\boxed{\text{mass of Ba(NO₂)₂ = 1.03 × 10³ g}}[/tex]
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