Justinlabarejosviz Justinlabarejosviz Math Answered 1.4x²zTypes of Polynomials:Coefficient:VariablesExponents:Degree:2.17a²2b + 3y3Types of Polynomials:Coefficient:VariablesExponents:Degree:3.15x² + 18 y² + 3x²y + ²Types of Polynomials:Coefficient:VariablesExponents:Degree:4.14c²b + 3z³ + 4Types of Polynomials:Coefficient:VariablesExponents:Degree:B.1.15x2+18y² + 3x² + 2=2.14c²b + 3b³ - 18c²b - 2b³=3.d²e+ 18b3 + 9 - 8d²e - 2b³ - 18=4.17a²b x 3y³=5.4c²b x 3b³ x18c2bPa answer nito please.