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Pump No.1 Can Empty A Tank In 16 Hours, Pump No.2 Can Empty The Same Tank In 12 Hours And Pump No.3 Can Empty It In 8 Hours. If All 3 Pumps Are Working Together

-2=2+5v+2v6(6v+6)-5=1+16v-4k+2(5k-6)=-3k -39-16+5n=-7(6+8n)+3can You Help Me To Solve It ?

Pump No.1 Can Empty A Tank In 16 Hours, Pump No.2 Can Empty The Same Tank In 12 Hours And Pump No.3 Can Empty It In 8 Hours. If All 3 Pumps Are Working Together

How To Solve A Pythagorean Theorem

Pump No.1 Can Empty A Tank In 16 Hours, Pump No.2 Can Empty The Same Tank In 12 Hours And Pump No.3 Can Empty It In 8 Hours. If All 3 Pumps Are Working Together

-2=2+5v+2v6(6v+6)-5=1+16v-4k+2(5k-6)=-3k -39-16+5n=-7(6+8n)+3can You Help Me To Solve It ?

Pump No.1 Can Empty A Tank In 16 Hours, Pump No.2 Can Empty The Same Tank In 12 Hours And Pump No.3 Can Empty It In 8 Hours. If All 3 Pumps Are Working Together

How To Solve A Pythagorean Theorem

How To Solve A Pythagorean Theorem

Pump No.1 Can Empty A Tank In 16 Hours, Pump No.2 Can Empty The Same Tank In 12 Hours And Pump No.3 Can Empty It In 8 Hours. If All 3 Pumps Are Working Together